Overview of key terms, equations, and skills for the simple harmonic motion of spring-mass systems, including comparing vertical and horizontal springs.
Log in DillanAsbury 4 years agoPosted 4 years ago. Direct link to DillanAsbury's post “Say we have a horizontal ...” Say we have a horizontal SHM frictionless spring-mass system. If I take another mass and drop it on top of the mass in oscillation, will it change the amplitude? I did a specific example and solved for the new amplitude with the new velocity after the mass was added and got the same amplitude. Am I correct to get the same amplitude? • (7 votes) abigailtityiwe 4 years agoPosted 4 years ago. Direct link to abigailtityiwe's post “you actually are correct ...” you actually are correct because by adding more mass you are simply increasing the force and hence the acceleration of mass moving through the distance in the same amount of time. the distance ( amplitude ) doesn't change because more mass was added, cause mass has no effect on it. (3 votes) Kevin Liang 3 years agoPosted 3 years ago. Direct link to Kevin Liang's post “I actually derived the fo...” I actually derived the formula of k = 4π^2m/T^2 by differentiating the sin(t) function of displacement twice to find the acceleration, then multiply by mass and divide by amplitude to find spring constant. First by finding the specific sin(t) function in the form of Asin(Bt), through the given amplitude(A) and period(T). 1. Knowing that B•T = 2π. Hence B = 2π/T. And A is just the Amplitude. Giving the Asin(Bt) equation as (Amplitude)sin(2πt/T) 2. Deriving once will give (A2π/T)sin(2πt/T), which is the function of velocity. 3. Deriving again will give -(A4π^2/T^2)sin(2πt/T) 4. Knowing that at k = (acceleration•mass)/displacement. Since we know the amplitude, and we also know the maximum displacement is at t = T/4, which is at Bt = π/2, which is when sin(Bt) = 1, simultaneously having the greatest acceleration of this oscillating system. 5. So we can get maximum acceleration = -A4π^2/T^2. Hence force = Ma, force = -A4Mπ^2/T^2. And k = Force divide by displacement, giving k = maximum force divide by the simultaneous maximum displacement, which gives k = (-A4Mπ^2/T^2)/A. 6. So the A cancels out, giving k = -4Mπ^2/T^2. This negative sign means the direction of force is inwards, which can be neglected. k = 4Mπ^2/T^2 Jordan Minke 3 years agoPosted 3 years ago. Direct link to Jordan Minke's post “would changing the mass (...” would changing the mass (and nothing else) of an object change the graph of simple harmonic motion? • (2 votes) Ziyad Nader 3 years agoPosted 3 years ago. Direct link to Ziyad Nader's post “Yes-changing the mass wou...” Yes-changing the mass would change the time taken to complete one full cycle (the period) and therefore would change the graph. (2 votes) tahtaaulia 5 years agoPosted 5 years ago. Direct link to tahtaaulia's post “So, why does loaded sprin...” So, why does loaded spring oscillation is s.h.m? (simple harmonic motion) • (2 votes) Izzy.Ivan.Tierney 3 years agoPosted 3 years ago. Direct link to Izzy.Ivan.Tierney's post “So for a mass undergoing ...” So for a mass undergoing SHM, where is the mass, when the force on it has its lowest magnitude? placidofrancescamarie 3 years agoPosted 3 years ago. Direct link to placidofrancescamarie's post “Explain what will happen ...” Explain what will happen to the periodic time? if you change the spring constant to the low value. • (1 vote) K.M. Intisar Uddin 3 years agoPosted 3 years ago. Direct link to K.M. Intisar Uddin's post “If I take a spring-mass s...” If I take a spring-mass system to 0 gravity , what would be the periodicity?? • (1 vote) shreyas0502 a year agoPosted a year ago. Direct link to shreyas0502's post “It would remain the same ...” It would remain the same everywhere in the universe as the time period is independent of acceleration by gravity. (1 vote) Ishan deep Tewari a year agoPosted a year ago. Direct link to Ishan deep Tewari 's post “which if the following is...” which if the following is/are characteristics of simple harmonic motion? • (1 vote) Sackey-Addoo Nicole20 4 years agoPosted 4 years ago. Direct link to Sackey-Addoo Nicole20's post “A 0.5 kg mass hangs on a ...” A 0.5 kg mass hangs on a spring, find it’s period • (0 votes) obiwan kenobi 4 years agoPosted 4 years ago. Direct link to obiwan kenobi's post “For a mass attached to a ...” For a mass attached to a spring, the period of oscillation is equal to 2π √(m/k). Plug in 0.5 for m and if you know what the spring constant k is you can solve. (2 votes) Rubio, Samantha 4 years agoPosted 4 years ago. Direct link to Rubio, Samantha's post “A 125 N object vibrates w...” A 125 N object vibrates with a period of 3.56s when hanging from a spring. What is the spring constant of the spring? • (0 votes) Dish*ta 2 years agoPosted 2 years ago. Direct link to Dish*ta's post “F=ma, (a=g=9.8 m/s/s)fin...” F=ma, (a=g=9.8 m/s/s) (2 votes)Want to join the conversation?
more mass means more force= more acceleration moving through a greater distance in the same amount of time.
I. The acceleration is constant
II. the frequency is independent of the amplitude
III. it requires a restoring force that point in a fixed direction
of oscillation
find m, substitute in
k=m*4*pi^2/T^2
voila, you get ur answer,
k = 39.735 N/m
